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20314114433 is a prime number
BaseRepresentation
bin10010111010110100…
…001100100110000001
31221102201120221020122
4102322310030212001
5313100403130213
613155425550025
71316255060264
oct227264144601
957381527218
1020314114433
118684873928
123b2b1a5315
131bb97a7c72
14da9cd0cdb
157dd616d08
hex4bad0c981

20314114433 has 2 divisors, whose sum is σ = 20314114434. Its totient is φ = 20314114432.

The previous prime is 20314114411. The next prime is 20314114463. The reversal of 20314114433 is 33441141302.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 17904580864 + 2409533569 = 133808^2 + 49087^2 .

It is a cyclic number.

It is not a de Polignac number, because 20314114433 - 26 = 20314114369 is a prime.

It is a super-2 number, since 2×203141144332 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (20314114463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10157057216 + 10157057217.

It is an arithmetic number, because the mean of its divisors is an integer number (10157057217).

Almost surely, 220314114433 is an apocalyptic number.

It is an amenable number.

20314114433 is a deficient number, since it is larger than the sum of its proper divisors (1).

20314114433 is an equidigital number, since it uses as much as digits as its factorization.

20314114433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 26.

Adding to 20314114433 its reverse (33441141302), we get a palindrome (53755255735).

The spelling of 20314114433 in words is "twenty billion, three hundred fourteen million, one hundred fourteen thousand, four hundred thirty-three".