Base | Representation |
---|---|
bin | 11101100011111011011… |
… | …101010000010111010011 |
3 | 21012012111202222201010010 |
4 | 131203323131100113103 |
5 | 231240343442023011 |
6 | 4153122052210003 |
7 | 266524026156600 |
oct | 35437335202723 |
9 | 7165452881103 |
10 | 2031443314131 |
11 | 713591878110 |
12 | 28985a309903 |
13 | 1197449620aa |
14 | 704728836a7 |
15 | 37c986a51a6 |
hex | 1d8fb7505d3 |
2031443314131 has 96 divisors (see below), whose sum is σ = 3533647749120. Its totient is φ = 1025996328000.
The previous prime is 2031443314127. The next prime is 2031443314139. The reversal of 2031443314131 is 1314133441302.
It is not a de Polignac number, because 2031443314131 - 22 = 2031443314127 is a prime.
It is a super-2 number, since 2×20314433141312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2031443314139) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 11387340 + ... + 11564358.
It is an arithmetic number, because the mean of its divisors is an integer number (36808830720).
Almost surely, 22031443314131 is an apocalyptic number.
2031443314131 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
2031443314131 is a deficient number, since it is larger than the sum of its proper divisors (1502204434989).
2031443314131 is a wasteful number, since it uses less digits than its factorization.
2031443314131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 177245 (or 177238 counting only the distinct ones).
The product of its (nonzero) digits is 10368, while the sum is 30.
Adding to 2031443314131 its reverse (1314133441302), we get a palindrome (3345576755433).
The spelling of 2031443314131 in words is "two trillion, thirty-one billion, four hundred forty-three million, three hundred fourteen thousand, one hundred thirty-one".
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