Base | Representation |
---|---|
bin | 11101100100110100100… |
… | …111010011100110010011 |
3 | 21012021222121101201000021 |
4 | 131210310213103212103 |
5 | 231244324434001011 |
6 | 4153401145404311 |
7 | 266556552041431 |
oct | 35446447234623 |
9 | 7167877351007 |
10 | 2032402250131 |
11 | 713a340a3a00 |
12 | 289a87499697 |
13 | 119868522346 |
14 | 70523d81d51 |
15 | 37d02974471 |
hex | 1d9349d3993 |
2032402250131 has 6 divisors (see below), whose sum is σ = 2233962803996. Its totient is φ = 1847638409100.
The previous prime is 2032402250113. The next prime is 2032402250141. The reversal of 2032402250131 is 1310522042302.
It is not a de Polignac number, because 2032402250131 - 237 = 1894963296659 is a prime.
It is a super-2 number, since 2×20324022501312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2032402250096 and 2032402250105.
It is not an unprimeable number, because it can be changed into a prime (2032402250141) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 8398356285 + ... + 8398356526.
Almost surely, 22032402250131 is an apocalyptic number.
2032402250131 is a deficient number, since it is larger than the sum of its proper divisors (201560553865).
2032402250131 is a wasteful number, since it uses less digits than its factorization.
2032402250131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16796712833 (or 16796712822 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 2032402250131 its reverse (1310522042302), we get a palindrome (3342924292433).
The spelling of 2032402250131 in words is "two trillion, thirty-two billion, four hundred two million, two hundred fifty thousand, one hundred thirty-one".
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