Base | Representation |
---|---|
bin | 101110001101100011111111… |
… | …101000110000001111010111 |
3 | 222122121202111021111220001011 |
4 | 232031203333220300033113 |
5 | 203114404401134221101 |
6 | 2000132052321513051 |
7 | 60544521504660403 |
oct | 5615437750601727 |
9 | 878552437456034 |
10 | 203242141320151 |
11 | 5983956529983a |
12 | 1a965831aa2787 |
13 | 89538619b7a3b |
14 | 3828d87730103 |
15 | 1876bdb719751 |
hex | b8d8ffa303d7 |
203242141320151 has 2 divisors, whose sum is σ = 203242141320152. Its totient is φ = 203242141320150.
The previous prime is 203242141320121. The next prime is 203242141320209. The reversal of 203242141320151 is 151023141242302.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-203242141320151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (203242141320121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101621070660075 + 101621070660076.
It is an arithmetic number, because the mean of its divisors is an integer number (101621070660076).
Almost surely, 2203242141320151 is an apocalyptic number.
203242141320151 is a deficient number, since it is larger than the sum of its proper divisors (1).
203242141320151 is an equidigital number, since it uses as much as digits as its factorization.
203242141320151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 203242141320151 its reverse (151023141242302), we get a palindrome (354265282562453).
The spelling of 203242141320151 in words is "two hundred three trillion, two hundred forty-two billion, one hundred forty-one million, three hundred twenty thousand, one hundred fifty-one".
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