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20331120113151 = 337579918033683
BaseRepresentation
bin1001001111101101101010…
…01100010011010111111111
32122222122011201101002011020
410213312311030103113333
510131101113222110101
6111123553155155223
74165606052366151
oct447666514232777
978878151332136
1020331120113151
11652941a2aaa11
122344382ba5b13
13b462a757b183
145040624a0ad1
15253cd4679136
hex127db53135ff

20331120113151 has 8 divisors (see below), whose sum is σ = 27108233788800. Its totient is φ = 13554043256472.

The previous prime is 20331120113147. The next prime is 20331120113153. The reversal of 20331120113151 is 15131102113302.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 20331120113151 - 22 = 20331120113147 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20331120113153) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7889445 + ... + 10144238.

It is an arithmetic number, because the mean of its divisors is an integer number (3388529223600).

Almost surely, 220331120113151 is an apocalyptic number.

20331120113151 is a deficient number, since it is larger than the sum of its proper divisors (6777113675649).

20331120113151 is a wasteful number, since it uses less digits than its factorization.

20331120113151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18409485.

The product of its (nonzero) digits is 540, while the sum is 24.

Adding to 20331120113151 its reverse (15131102113302), we get a palindrome (35462222226453).

The spelling of 20331120113151 in words is "twenty trillion, three hundred thirty-one billion, one hundred twenty million, one hundred thirteen thousand, one hundred fifty-one".

Divisors: 1 3 375799 1127397 18033683 54101049 6777040037717 20331120113151