Base | Representation |
---|---|
bin | 1011110101110001011… |
… | …1000100001110110111 |
3 | 201110001012110201202021 |
4 | 2331130113010032313 |
5 | 11313042212412211 |
6 | 233240250454011 |
7 | 20460523041325 |
oct | 2753427041667 |
9 | 643035421667 |
10 | 203413013431 |
11 | 792a3385761 |
12 | 3350a734307 |
13 | 16249450354 |
14 | 9bb94b8d15 |
15 | 5457dec771 |
hex | 2f5c5c43b7 |
203413013431 has 2 divisors, whose sum is σ = 203413013432. Its totient is φ = 203413013430.
The previous prime is 203413013371. The next prime is 203413013437. The reversal of 203413013431 is 134310314302.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 203413013431 - 213 = 203413005239 is a prime.
It is a super-2 number, since 2×2034130134312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 203413013396 and 203413013405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (203413013437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101706506715 + 101706506716.
It is an arithmetic number, because the mean of its divisors is an integer number (101706506716).
Almost surely, 2203413013431 is an apocalyptic number.
203413013431 is a deficient number, since it is larger than the sum of its proper divisors (1).
203413013431 is an equidigital number, since it uses as much as digits as its factorization.
203413013431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 203413013431 its reverse (134310314302), we get a palindrome (337723327733).
The spelling of 203413013431 in words is "two hundred three billion, four hundred thirteen million, thirteen thousand, four hundred thirty-one".
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