Base | Representation |
---|---|
bin | 10010111100011100… |
… | …000001010111100111 |
3 | 1221111121210200221121 |
4 | 102330130001113213 |
5 | 313124340101211 |
6 | 13202241154411 |
7 | 1320035315161 |
oct | 227434012747 |
9 | 57447720847 |
10 | 20341331431 |
11 | 8699173413 |
12 | 3b3832ba07 |
13 | 1bc23172b5 |
14 | dad777931 |
15 | 7e0be1271 |
hex | 4bc7015e7 |
20341331431 has 2 divisors, whose sum is σ = 20341331432. Its totient is φ = 20341331430.
The previous prime is 20341331393. The next prime is 20341331441. The reversal of 20341331431 is 13413314302.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20341331431 - 213 = 20341323239 is a prime.
It is a super-2 number, since 2×203413314312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 20341331396 and 20341331405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20341331441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10170665715 + 10170665716.
It is an arithmetic number, because the mean of its divisors is an integer number (10170665716).
Almost surely, 220341331431 is an apocalyptic number.
20341331431 is a deficient number, since it is larger than the sum of its proper divisors (1).
20341331431 is an equidigital number, since it uses as much as digits as its factorization.
20341331431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 20341331431 its reverse (13413314302), we get a palindrome (33754645733).
The spelling of 20341331431 in words is "twenty billion, three hundred forty-one million, three hundred thirty-one thousand, four hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •