Base | Representation |
---|---|
bin | 11101100110101011110… |
… | …001001010010000011101 |
3 | 21012111010221000002002121 |
4 | 131212223301022100131 |
5 | 231312423214301023 |
6 | 4154331400422541 |
7 | 266660234626354 |
oct | 35465361122035 |
9 | 7174127002077 |
10 | 2034401322013 |
11 | 71486a567225 |
12 | 28a344a77a51 |
13 | 119ac6733108 |
14 | 7067367899b |
15 | 37dbd201d5d |
hex | 1d9abc4a41d |
2034401322013 has 2 divisors, whose sum is σ = 2034401322014. Its totient is φ = 2034401322012.
The previous prime is 2034401321963. The next prime is 2034401322043. The reversal of 2034401322013 is 3102231044302.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1162562681284 + 871838640729 = 1078222^2 + 933723^2 .
It is a cyclic number.
It is not a de Polignac number, because 2034401322013 - 29 = 2034401321501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2034401322043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1017200661006 + 1017200661007.
It is an arithmetic number, because the mean of its divisors is an integer number (1017200661007).
Almost surely, 22034401322013 is an apocalyptic number.
It is an amenable number.
2034401322013 is a deficient number, since it is larger than the sum of its proper divisors (1).
2034401322013 is an equidigital number, since it uses as much as digits as its factorization.
2034401322013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 2034401322013 its reverse (3102231044302), we get a palindrome (5136632366315).
The spelling of 2034401322013 in words is "two trillion, thirty-four billion, four hundred one million, three hundred twenty-two thousand, thirteen".
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