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20344243301183 is a prime number
BaseRepresentation
bin1001010000000110000110…
…11001010010101100111111
32200000220001021222002211102
410220003003121102230333
510131310002241114213
6111134003310443315
74166552212553444
oct450030331225477
980026037862742
1020344243301183
116533a43a7435a
122346a25b0353b
13b475b9321ba9
145049493359cb
15254301811158
hex1280c3652b3f

20344243301183 has 2 divisors, whose sum is σ = 20344243301184. Its totient is φ = 20344243301182.

The previous prime is 20344243301177. The next prime is 20344243301203. The reversal of 20344243301183 is 38110334244302.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20344243301183 is a prime.

It is a super-4 number, since 4×203442433011834 (a number of 54 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20344243304183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10172121650591 + 10172121650592.

It is an arithmetic number, because the mean of its divisors is an integer number (10172121650592).

Almost surely, 220344243301183 is an apocalyptic number.

20344243301183 is a deficient number, since it is larger than the sum of its proper divisors (1).

20344243301183 is an equidigital number, since it uses as much as digits as its factorization.

20344243301183 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 165888, while the sum is 38.

Adding to 20344243301183 its reverse (38110334244302), we get a palindrome (58454577545485).

The spelling of 20344243301183 in words is "twenty trillion, three hundred forty-four billion, two hundred forty-three million, three hundred one thousand, one hundred eighty-three".