Base | Representation |
---|---|
bin | 10011000000000000… |
… | …001001000111110101 |
3 | 1221122210022212221021 |
4 | 103000000021013311 |
5 | 313240142211041 |
6 | 13212215021141 |
7 | 1321362522004 |
oct | 230000110765 |
9 | 57583285837 |
10 | 20401132021 |
11 | 87199a8496 |
12 | 3b5436a7b1 |
13 | 1c0182456a |
14 | db76a2c3b |
15 | 7e60a4cd1 |
hex | 4c00091f5 |
20401132021 has 2 divisors, whose sum is σ = 20401132022. Its totient is φ = 20401132020.
The previous prime is 20401132009. The next prime is 20401132027. The reversal of 20401132021 is 12023110402.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 17537704900 + 2863427121 = 132430^2 + 53511^2 .
It is a cyclic number.
It is not a de Polignac number, because 20401132021 - 231 = 18253648373 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20401131986 and 20401132004.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20401132027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10200566010 + 10200566011.
It is an arithmetic number, because the mean of its divisors is an integer number (10200566011).
Almost surely, 220401132021 is an apocalyptic number.
It is an amenable number.
20401132021 is a deficient number, since it is larger than the sum of its proper divisors (1).
20401132021 is an equidigital number, since it uses as much as digits as its factorization.
20401132021 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 16.
Adding to 20401132021 its reverse (12023110402), we get a palindrome (32424242423).
The spelling of 20401132021 in words is "twenty billion, four hundred one million, one hundred thirty-two thousand, twenty-one".
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