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204011513 is a prime number
BaseRepresentation
bin11000010100011…
…11011111111001
3112012212212011222
430022033133321
5404211332023
632124401425
75025032516
oct1412173771
9465785158
10204011513
11a5182962
12583a6275
1333360194
141d14830d
1512d9ccc8
hexc28f7f9

204011513 has 2 divisors, whose sum is σ = 204011514. Its totient is φ = 204011512.

The previous prime is 204011503. The next prime is 204011539. The reversal of 204011513 is 315110402.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 203005504 + 1006009 = 14248^2 + 1003^2 .

It is a cyclic number.

It is not a de Polignac number, because 204011513 - 212 = 204007417 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 204011491 and 204011500.

It is not a weakly prime, because it can be changed into another prime (204011503) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 102005756 + 102005757.

It is an arithmetic number, because the mean of its divisors is an integer number (102005757).

Almost surely, 2204011513 is an apocalyptic number.

It is an amenable number.

204011513 is a deficient number, since it is larger than the sum of its proper divisors (1).

204011513 is an equidigital number, since it uses as much as digits as its factorization.

204011513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 204011513 is about 14283.2598870146. The cubic root of 204011513 is about 588.6876057168.

Adding to 204011513 its reverse (315110402), we get a palindrome (519121915).

The spelling of 204011513 in words is "two hundred four million, eleven thousand, five hundred thirteen".