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20401331001 = 36800443667
BaseRepresentation
bin10011000000000000…
…111001101100111001
31221122210200222212220
4103000000321230321
5313240220043001
613212223154253
71321364311062
oct230000715471
957583628786
1020401331001
11871a023a37
123b54445989
131c01893cbc
14db7715569
157e60e3c36
hex4c0039b39

20401331001 has 4 divisors (see below), whose sum is σ = 27201774672. Its totient is φ = 13600887332.

The previous prime is 20401330991. The next prime is 20401331003. The reversal of 20401331001 is 10013310402.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20401331001 - 29 = 20401330489 is a prime.

It is a super-2 number, since 2×204013310012 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (20401331003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3400221831 + ... + 3400221836.

It is an arithmetic number, because the mean of its divisors is an integer number (6800443668).

Almost surely, 220401331001 is an apocalyptic number.

It is an amenable number.

20401331001 is a deficient number, since it is larger than the sum of its proper divisors (6800443671).

20401331001 is an equidigital number, since it uses as much as digits as its factorization.

20401331001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6800443670.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 20401331001 its reverse (10013310402), we get a palindrome (30414641403).

The spelling of 20401331001 in words is "twenty billion, four hundred one million, three hundred thirty-one thousand, one".

Divisors: 1 3 6800443667 20401331001