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2040300515131 is a prime number
BaseRepresentation
bin11101101100001011011…
…000110010111100111011
321020001101001101010201121
4131230023120302330323
5231412013412441011
64201145012530111
7300256356142204
oct35541330627473
97201331333647
102040300515131
117173174a533a
1228b510620937
1311a526965028
1470a72d265ab
1538116075e71
hex1db0b632f3b

2040300515131 has 2 divisors, whose sum is σ = 2040300515132. Its totient is φ = 2040300515130.

The previous prime is 2040300515107. The next prime is 2040300515189. The reversal of 2040300515131 is 1315150030402.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2040300515131 is a prime.

It is a super-2 number, since 2×20403005151312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2040300515096 and 2040300515105.

It is not a weakly prime, because it can be changed into another prime (2040300515431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1020150257565 + 1020150257566.

It is an arithmetic number, because the mean of its divisors is an integer number (1020150257566).

Almost surely, 22040300515131 is an apocalyptic number.

2040300515131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2040300515131 is an equidigital number, since it uses as much as digits as its factorization.

2040300515131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1800, while the sum is 25.

Adding to 2040300515131 its reverse (1315150030402), we get a palindrome (3355450545533).

The spelling of 2040300515131 in words is "two trillion, forty billion, three hundred million, five hundred fifteen thousand, one hundred thirty-one".