204040131100111 has 4 divisors (see below), whose sum is σ = 211075997689800. Its totient is φ = 197004264510424.

The previous prime is 204040131100093. The next prime is 204040131100219. The reversal of 204040131100111 is 111001131040402.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 204040131100111 - 2¹³ = 204040131091919 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (204040131100811) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3517933294801 + ... + 3517933294858.

It is an arithmetic number, because the mean of its divisors is an integer number (52768999422450).

Almost surely, 2^{204040131100111} is an apocalyptic number.

204040131100111 is a deficient number, since it is larger than the sum of its proper divisors (7035866589689).

204040131100111 is an equidigital number, since it uses as much as digits as its factorization.

204040131100111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7035866589688.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 204040131100111 its reverse (111001131040402), we get a palindrome (315041262140513).

The spelling of 204040131100111 in words is "two hundred four trillion, forty billion, one hundred thirty-one million, one hundred thousand, one hundred eleven".