20411412443333 has 4 divisors (see below), whose sum is σ = 20411424715968. Its totient is φ = 20411400170700.

The previous prime is 20411412443329. The next prime is 20411412443407. The reversal of 20411412443333 is 33334421411402.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20411412443333 - 2² = 20411412443329 is a prime.

It is a super-2 number, since 2×20411412443333² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20411412443293 and 20411412443302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20411412443033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3160541 + ... + 7128242.

It is an arithmetic number, because the mean of its divisors is an integer number (5102856178992).

Almost surely, 2^{20411412443333} is an apocalyptic number.

It is an amenable number.

20411412443333 is a deficient number, since it is larger than the sum of its proper divisors (12272635).

20411412443333 is a wasteful number, since it uses less digits than its factorization.

20411412443333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12272634.

The product of its (nonzero) digits is 82944, while the sum is 35.

Adding to 20411412443333 its reverse (33334421411402), we get a palindrome (53745833854735).

The spelling of 20411412443333 in words is "twenty trillion, four hundred eleven billion, four hundred twelve million, four hundred forty-three thousand, three hundred thirty-three".