Base | Representation |
---|---|
bin | 1001010010000110011101… |
… | …01011100010011110000111 |
3 | 2200021110220200001022110012 |
4 | 10221003032223202132013 |
5 | 10133422113420013341 |
6 | 111225401141420435 |
7 | 4204541640020201 |
oct | 451031653423607 |
9 | 80243820038405 |
10 | 20413152110471 |
11 | 656019521871a |
12 | 235825740a71b |
13 | b50c4b681463 |
14 | 508005063771 |
15 | 255ed622b0eb |
hex | 1290ceae2787 |
20413152110471 has 2 divisors, whose sum is σ = 20413152110472. Its totient is φ = 20413152110470.
The previous prime is 20413152110459. The next prime is 20413152110479. The reversal of 20413152110471 is 17401125131402.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20413152110471 is a prime.
It is a super-3 number, since 3×204131521104713 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20413152110479) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10206576055235 + 10206576055236.
It is an arithmetic number, because the mean of its divisors is an integer number (10206576055236).
Almost surely, 220413152110471 is an apocalyptic number.
20413152110471 is a deficient number, since it is larger than the sum of its proper divisors (1).
20413152110471 is an equidigital number, since it uses as much as digits as its factorization.
20413152110471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6720, while the sum is 32.
Adding to 20413152110471 its reverse (17401125131402), we get a palindrome (37814277241873).
The spelling of 20413152110471 in words is "twenty trillion, four hundred thirteen billion, one hundred fifty-two million, one hundred ten thousand, four hundred seventy-one".
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