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204141115 = 540828223
BaseRepresentation
bin11000010101011…
…11001000111011
3112020010102222001
430022233020323
5404230003430
632131241431
75026112413
oct1412571073
9466112861
10204141115
11a5261272
1258449277
13333a7179
141d17d643
1512dc63ca
hexc2af23b

204141115 has 4 divisors (see below), whose sum is σ = 244969344. Its totient is φ = 163312888.

The previous prime is 204141103. The next prime is 204141131. The reversal of 204141115 is 511141402.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 511141402 = 2255570701.

It is a cyclic number.

It is not a de Polignac number, because 204141115 - 215 = 204108347 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 204141092 and 204141101.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20414107 + ... + 20414116.

It is an arithmetic number, because the mean of its divisors is an integer number (61242336).

Almost surely, 2204141115 is an apocalyptic number.

204141115 is a deficient number, since it is larger than the sum of its proper divisors (40828229).

204141115 is an equidigital number, since it uses as much as digits as its factorization.

204141115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40828228.

The product of its (nonzero) digits is 160, while the sum is 19.

The square root of 204141115 is about 14287.7960161811. The cubic root of 204141115 is about 588.8122374752.

Adding to 204141115 its reverse (511141402), we get a palindrome (715282517).

The spelling of 204141115 in words is "two hundred four million, one hundred forty-one thousand, one hundred fifteen".

Divisors: 1 5 40828223 204141115