Base | Representation |
---|---|
bin | 1001010010011001101000… |
… | …01101010101101001101011 |
3 | 2200022110111000200211000202 |
4 | 10221030310031111221223 |
5 | 10134104204010414032 |
6 | 111234222402422415 |
7 | 4205355005411123 |
oct | 451146415255153 |
9 | 80273430624022 |
10 | 20423445404267 |
11 | 65645975466a4 |
12 | 235a24a661a0b |
13 | b51bcc05c149 |
14 | 508700131c83 |
15 | 2563d9c20d62 |
hex | 129334355a6b |
20423445404267 has 2 divisors, whose sum is σ = 20423445404268. Its totient is φ = 20423445404266.
The previous prime is 20423445404231. The next prime is 20423445404269. The reversal of 20423445404267 is 76240454432402.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20423445404267 - 26 = 20423445404203 is a prime.
Together with 20423445404269, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (20423445404269) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10211722702133 + 10211722702134.
It is an arithmetic number, because the mean of its divisors is an integer number (10211722702134).
Almost surely, 220423445404267 is an apocalyptic number.
20423445404267 is a deficient number, since it is larger than the sum of its proper divisors (1).
20423445404267 is an equidigital number, since it uses as much as digits as its factorization.
20423445404267 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5160960, while the sum is 47.
Adding to 20423445404267 its reverse (76240454432402), we get a palindrome (96663899836669).
The spelling of 20423445404267 in words is "twenty trillion, four hundred twenty-three billion, four hundred forty-five million, four hundred four thousand, two hundred sixty-seven".
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