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204312151153 = 1118573831923
BaseRepresentation
bin1011111001000111110…
…1000000010001110001
3201112100212100122211101
42332101331000101301
511321412402314103
6233505410244401
720522021426155
oct2762175002161
9645325318741
10204312151153
1179714979190
123371b886701
13163608043c6
149c62a8d065
1554abd08a1d
hex2f91f40471

204312151153 has 4 divisors (see below), whose sum is σ = 222885983088. Its totient is φ = 185738319220.

The previous prime is 204312151129. The next prime is 204312151157. The reversal of 204312151153 is 351151213402.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 204312151153 - 221 = 204310054001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (204312151157) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9286915951 + ... + 9286915972.

It is an arithmetic number, because the mean of its divisors is an integer number (55721495772).

Almost surely, 2204312151153 is an apocalyptic number.

It is an amenable number.

204312151153 is a deficient number, since it is larger than the sum of its proper divisors (18573831935).

204312151153 is a wasteful number, since it uses less digits than its factorization.

204312151153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18573831934.

The product of its (nonzero) digits is 3600, while the sum is 28.

Adding to 204312151153 its reverse (351151213402), we get a palindrome (555463364555).

The spelling of 204312151153 in words is "two hundred four billion, three hundred twelve million, one hundred fifty-one thousand, one hundred fifty-three".

Divisors: 1 11 18573831923 204312151153