Base | Representation |
---|---|
bin | 1001010010101000101011… |
… | …01111001010101011011011 |
3 | 2200100020100001012202011120 |
4 | 10221110111233022223123 |
5 | 10134222230133104430 |
6 | 111242040153300323 |
7 | 4206062133326133 |
oct | 451242557125333 |
9 | 80306301182146 |
10 | 20431524113115 |
11 | 6567a62793185 |
12 | 235b9241046a3 |
13 | b528b899ca3b |
14 | 508c69047ac3 |
15 | 25670e0b7610 |
hex | 129515bcaadb |
20431524113115 has 32 divisors (see below), whose sum is σ = 34652605718016. Its totient is φ = 10244209006080.
The previous prime is 20431524113107. The next prime is 20431524113129. The reversal of 20431524113115 is 51131142513402.
It is not a de Polignac number, because 20431524113115 - 23 = 20431524113107 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 45144951 + ... + 45595280.
It is an arithmetic number, because the mean of its divisors is an integer number (1082893928688).
Almost surely, 220431524113115 is an apocalyptic number.
20431524113115 is a deficient number, since it is larger than the sum of its proper divisors (14221081604901).
20431524113115 is a wasteful number, since it uses less digits than its factorization.
20431524113115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 90741139.
The product of its (nonzero) digits is 14400, while the sum is 33.
Adding to 20431524113115 its reverse (51131142513402), we get a palindrome (71562666626517).
The spelling of 20431524113115 in words is "twenty trillion, four hundred thirty-one billion, five hundred twenty-four million, one hundred thirteen thousand, one hundred fifteen".
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