Base | Representation |
---|---|
bin | 11101101110111111010… |
… | …111101001000011011011 |
3 | 21020100011111021111222121 |
4 | 131232333113221003123 |
5 | 231434204422030243 |
6 | 4202404401202111 |
7 | 300424243242511 |
oct | 35567727510333 |
9 | 7210144244877 |
10 | 2043320111323 |
11 | 718626a2a687 |
12 | 290013930337 |
13 | 11a8b841ac3a |
14 | 70c7bd904b1 |
15 | 382411db1ed |
hex | 1dbbf5e90db |
2043320111323 has 2 divisors, whose sum is σ = 2043320111324. Its totient is φ = 2043320111322.
The previous prime is 2043320111321. The next prime is 2043320111341. The reversal of 2043320111323 is 3231110233402.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2043320111323 - 21 = 2043320111321 is a prime.
It is a super-2 number, since 2×20433201113232 (a number of 25 digits) contains 22 as substring.
Together with 2043320111321, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (2043320111321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1021660055661 + 1021660055662.
It is an arithmetic number, because the mean of its divisors is an integer number (1021660055662).
Almost surely, 22043320111323 is an apocalyptic number.
2043320111323 is a deficient number, since it is larger than the sum of its proper divisors (1).
2043320111323 is an equidigital number, since it uses as much as digits as its factorization.
2043320111323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 2043320111323 its reverse (3231110233402), we get a palindrome (5274430344725).
The spelling of 2043320111323 in words is "two trillion, forty-three billion, three hundred twenty million, one hundred eleven thousand, three hundred twenty-three".
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