Base | Representation |
---|---|
bin | 1011111001001101000… |
… | …0011001100001010101 |
3 | 201112102101111022221221 |
4 | 2332103100121201111 |
5 | 11321434001400001 |
6 | 233511511010341 |
7 | 20522405306653 |
oct | 2762320314125 |
9 | 645371438857 |
10 | 204334012501 |
11 | 7972624aa13 |
12 | 337270699b1 |
13 | 163651b9b08 |
14 | 9c6593ddd3 |
15 | 54adbc61a1 |
hex | 2f93419855 |
204334012501 has 4 divisors (see below), whose sum is σ = 204743500000. Its totient is φ = 203924525004.
The previous prime is 204334012489. The next prime is 204334012511. The reversal of 204334012501 is 105210433402.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 204334012501 - 25 = 204334012469 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (204334012511) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 204743001 + ... + 204743998.
It is an arithmetic number, because the mean of its divisors is an integer number (51185875000).
Almost surely, 2204334012501 is an apocalyptic number.
It is an amenable number.
204334012501 is a deficient number, since it is larger than the sum of its proper divisors (409487499).
204334012501 is an equidigital number, since it uses as much as digits as its factorization.
204334012501 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 409487498.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 204334012501 its reverse (105210433402), we get a palindrome (309544445903).
The spelling of 204334012501 in words is "two hundred four billion, three hundred thirty-four million, twelve thousand, five hundred one".
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