Base | Representation |
---|---|
bin | 11101101111000001010… |
… | …001110010011001001111 |
3 | 21020100020201112021221011 |
4 | 131233001101302121033 |
5 | 231434241121144101 |
6 | 4202411503350051 |
7 | 300425112353002 |
oct | 35570121623117 |
9 | 7210221467834 |
10 | 2043352131151 |
11 | 71864300a651 |
12 | 2900225b2327 |
13 | 11a8c1c4c396 |
14 | 70c82327539 |
15 | 38243e13751 |
hex | 1dbc147264f |
2043352131151 has 8 divisors (see below), whose sum is σ = 2073834481824. Its totient is φ = 2012917079040.
The previous prime is 2043352131049. The next prime is 2043352131269. The reversal of 2043352131151 is 1511312533402.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2043352131151 - 221 = 2043350033999 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2043352138151) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11737590 + ... + 11910403.
It is an arithmetic number, because the mean of its divisors is an integer number (259229310228).
Almost surely, 22043352131151 is an apocalyptic number.
2043352131151 is a deficient number, since it is larger than the sum of its proper divisors (30482350673).
2043352131151 is a wasteful number, since it uses less digits than its factorization.
2043352131151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23649281.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 2043352131151 its reverse (1511312533402), we get a palindrome (3554664664553).
The spelling of 2043352131151 in words is "two trillion, forty-three billion, three hundred fifty-two million, one hundred thirty-one thousand, one hundred fifty-one".
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