Base | Representation |
---|---|
bin | 101110011101100100010101… |
… | …000100000000110010000111 |
3 | 222210111220110012000121022011 |
4 | 232131210111010000302013 |
5 | 203240414420134240421 |
6 | 2002333231412315051 |
7 | 61020136363014454 |
oct | 5635442504006207 |
9 | 883456405017264 |
10 | 204342012415111 |
11 | 5a122a6290653a |
12 | 1ab02a26612a87 |
13 | 8a034a4b6ba2c |
14 | 38662c5a4082b |
15 | 1895610c064e1 |
hex | b9d915100c87 |
204342012415111 has 2 divisors, whose sum is σ = 204342012415112. Its totient is φ = 204342012415110.
The previous prime is 204342012415097. The next prime is 204342012415139. The reversal of 204342012415111 is 111514210243402.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 204342012415111 - 213 = 204342012406919 is a prime.
It is a super-2 number, since 2×2043420124151112 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (204342012415711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 102171006207555 + 102171006207556.
It is an arithmetic number, because the mean of its divisors is an integer number (102171006207556).
Almost surely, 2204342012415111 is an apocalyptic number.
204342012415111 is a deficient number, since it is larger than the sum of its proper divisors (1).
204342012415111 is an equidigital number, since it uses as much as digits as its factorization.
204342012415111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7680, while the sum is 31.
Adding to 204342012415111 its reverse (111514210243402), we get a palindrome (315856222658513).
The spelling of 204342012415111 in words is "two hundred four trillion, three hundred forty-two billion, twelve million, four hundred fifteen thousand, one hundred eleven".
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