Base | Representation |
---|---|
bin | 1001010010101101111001… |
… | …00101011000011111001011 |
3 | 2200100111120010110101002212 |
4 | 10221112330211120133023 |
5 | 10134243443233441212 |
6 | 111243222030415335 |
7 | 4206221403360116 |
oct | 451267445303713 |
9 | 80314503411085 |
10 | 20434323343307 |
11 | 6569169895265 |
12 | 236038566154b |
13 | b52c438ba773 |
14 | 509052b0b57d |
15 | 256824bede22 |
hex | 1295bc9587cb |
20434323343307 has 2 divisors, whose sum is σ = 20434323343308. Its totient is φ = 20434323343306.
The previous prime is 20434323343241. The next prime is 20434323343309. The reversal of 20434323343307 is 70334332343402.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20434323343307 - 28 = 20434323343051 is a prime.
Together with 20434323343309, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (20434323343309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10217161671653 + 10217161671654.
It is an arithmetic number, because the mean of its divisors is an integer number (10217161671654).
Almost surely, 220434323343307 is an apocalyptic number.
20434323343307 is a deficient number, since it is larger than the sum of its proper divisors (1).
20434323343307 is an equidigital number, since it uses as much as digits as its factorization.
20434323343307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1306368, while the sum is 41.
Adding to 20434323343307 its reverse (70334332343402), we get a palindrome (90768655686709).
The spelling of 20434323343307 in words is "twenty trillion, four hundred thirty-four billion, three hundred twenty-three million, three hundred forty-three thousand, three hundred seven".
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