Base | Representation |
---|---|
bin | 101110011101100101100010… |
… | …011101110110011011111111 |
3 | 222210112000210200121021200011 |
4 | 232131211202131312123333 |
5 | 203240430100111042421 |
6 | 2002334004322244051 |
7 | 61020213512053624 |
oct | 5635454235663377 |
9 | 883460720537604 |
10 | 204343311034111 |
11 | 5a123569950187 |
12 | 1ab031294b6627 |
13 | 8a03650c12242 |
14 | 38663aa2c234b |
15 | 1895689c224e1 |
hex | b9d9627766ff |
204343311034111 has 2 divisors, whose sum is σ = 204343311034112. Its totient is φ = 204343311034110.
The previous prime is 204343311034067. The next prime is 204343311034123. The reversal of 204343311034111 is 111430113343402.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 204343311034111 - 29 = 204343311033599 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (204343311034151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 102171655517055 + 102171655517056.
It is an arithmetic number, because the mean of its divisors is an integer number (102171655517056).
Almost surely, 2204343311034111 is an apocalyptic number.
204343311034111 is a deficient number, since it is larger than the sum of its proper divisors (1).
204343311034111 is an equidigital number, since it uses as much as digits as its factorization.
204343311034111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 204343311034111 its reverse (111430113343402), we get a palindrome (315773424377513).
The spelling of 204343311034111 in words is "two hundred four trillion, three hundred forty-three billion, three hundred eleven million, thirty-four thousand, one hundred eleven".
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