20441130255551 has 4 divisors (see below), whose sum is σ = 20450392210752. Its totient is φ = 20431868300352.

The previous prime is 20441130255529. The next prime is 20441130255613. The reversal of 20441130255551 is 15555203114402.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20441130255551 - 2⁶ = 20441130255487 is a prime.

It is a super-3 number, since 3×20441130255551³ (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20441130255251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4630974290 + ... + 4630978703.

It is an arithmetic number, because the mean of its divisors is an integer number (5112598052688).

Almost surely, 2^{20441130255551} is an apocalyptic number.

20441130255551 is a deficient number, since it is larger than the sum of its proper divisors (9261955201).

20441130255551 is an equidigital number, since it uses as much as digits as its factorization.

20441130255551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9261955200.

The product of its (nonzero) digits is 120000, while the sum is 38.

Adding to 20441130255551 its reverse (15555203114402), we get a palindrome (35996333369953).

The spelling of 20441130255551 in words is "twenty trillion, four hundred forty-one billion, one hundred thirty million, two hundred fifty-five thousand, five hundred fifty-one".