Search a number
-
+
20442113 = 31659423
BaseRepresentation
bin100110111111…
…0110000000001
31102110120022022
41031332300001
520213121423
62010051225
7335516666
oct115766001
942416268
1020442113
11105a250a
126a19b15
134309733
142a01a6d
151bdbdc8
hex137ec01

20442113 has 4 divisors (see below), whose sum is σ = 21101568. Its totient is φ = 19782660.

The previous prime is 20442091. The next prime is 20442127. The reversal of 20442113 is 31124402.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20442113 - 28 = 20441857 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20442091 and 20442100.

It is not an unprimeable number, because it can be changed into a prime (20442173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 329681 + ... + 329742.

It is an arithmetic number, because the mean of its divisors is an integer number (5275392).

Almost surely, 220442113 is an apocalyptic number.

It is an amenable number.

20442113 is a deficient number, since it is larger than the sum of its proper divisors (659455).

20442113 is an equidigital number, since it uses as much as digits as its factorization.

20442113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 659454.

The product of its (nonzero) digits is 192, while the sum is 17.

The square root of 20442113 is about 4521.2955001858. The cubic root of 20442113 is about 273.4273341505.

Adding to 20442113 its reverse (31124402), we get a palindrome (51566515).

The spelling of 20442113 in words is "twenty million, four hundred forty-two thousand, one hundred thirteen".

Divisors: 1 31 659423 20442113