Base | Representation |
---|---|
bin | 1001010010111110010001… |
… | …11110111011011111001011 |
3 | 2200101100021021100221210111 |
4 | 10221133020332323133023 |
5 | 10134420003023121301 |
6 | 111251235033255151 |
7 | 4206652413650632 |
oct | 451371076733713 |
9 | 80340237327714 |
10 | 20443121301451 |
11 | 6571974029452 |
12 | 236201bb644b7 |
13 | b53a1654a264 |
14 | 50964936c519 |
15 | 256b8c2bb551 |
hex | 1297c8fbb7cb |
20443121301451 has 2 divisors, whose sum is σ = 20443121301452. Its totient is φ = 20443121301450.
The previous prime is 20443121301401. The next prime is 20443121301469. The reversal of 20443121301451 is 15410312134402.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20443121301451 - 215 = 20443121268683 is a prime.
It is not a weakly prime, because it can be changed into another prime (20443121301401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10221560650725 + 10221560650726.
It is an arithmetic number, because the mean of its divisors is an integer number (10221560650726).
Almost surely, 220443121301451 is an apocalyptic number.
20443121301451 is a deficient number, since it is larger than the sum of its proper divisors (1).
20443121301451 is an equidigital number, since it uses as much as digits as its factorization.
20443121301451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 20443121301451 its reverse (15410312134402), we get a palindrome (35853433435853).
The spelling of 20443121301451 in words is "twenty trillion, four hundred forty-three billion, one hundred twenty-one million, three hundred one thousand, four hundred fifty-one".
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