Base | Representation |
---|---|
bin | 11101110000000001110… |
… | …010010111111110101011 |
3 | 21020110001011001000222211 |
4 | 131300001302113332223 |
5 | 231444000202244111 |
6 | 4203111124425551 |
7 | 300463663543024 |
oct | 35600162277653 |
9 | 7213034030884 |
10 | 2044434415531 |
11 | 719048a24952 |
12 | 290284b482b7 |
13 | 11aa35239641 |
14 | 70d45d73c4b |
15 | 382a8e4a521 |
hex | 1dc01c97fab |
2044434415531 has 2 divisors, whose sum is σ = 2044434415532. Its totient is φ = 2044434415530.
The previous prime is 2044434415493. The next prime is 2044434415547. The reversal of 2044434415531 is 1355144344402.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2044434415531 - 215 = 2044434382763 is a prime.
It is a super-2 number, since 2×20444344155312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2044434415561) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1022217207765 + 1022217207766.
It is an arithmetic number, because the mean of its divisors is an integer number (1022217207766).
Almost surely, 22044434415531 is an apocalyptic number.
2044434415531 is a deficient number, since it is larger than the sum of its proper divisors (1).
2044434415531 is an equidigital number, since it uses as much as digits as its factorization.
2044434415531 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 460800, while the sum is 40.
Adding to 2044434415531 its reverse (1355144344402), we get a palindrome (3399578759933).
The spelling of 2044434415531 in words is "two trillion, forty-four billion, four hundred thirty-four million, four hundred fifteen thousand, five hundred thirty-one".
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