Base | Representation |
---|---|
bin | 1001010011010001101010… |
… | …10001110100111110111111 |
3 | 2200102100010112122121001022 |
4 | 10221220311101310332333 |
5 | 10140102311200120341 |
6 | 111300115431534355 |
7 | 4210501331353253 |
oct | 451506521647677 |
9 | 80370115577038 |
10 | 20453528129471 |
11 | 6576324452368 |
12 | 236404522a3bb |
13 | b549b45c9b68 |
14 | 509d55552263 |
15 | 25709ac3ae4b |
hex | 129a35474fbf |
20453528129471 has 2 divisors, whose sum is σ = 20453528129472. Its totient is φ = 20453528129470.
The previous prime is 20453528129429. The next prime is 20453528129477. The reversal of 20453528129471 is 17492182535402.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20453528129471 - 26 = 20453528129407 is a prime.
It is a super-3 number, since 3×204535281294713 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20453528129477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10226764064735 + 10226764064736.
It is an arithmetic number, because the mean of its divisors is an integer number (10226764064736).
Almost surely, 220453528129471 is an apocalyptic number.
20453528129471 is a deficient number, since it is larger than the sum of its proper divisors (1).
20453528129471 is an equidigital number, since it uses as much as digits as its factorization.
20453528129471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4838400, while the sum is 53.
The spelling of 20453528129471 in words is "twenty trillion, four hundred fifty-three billion, five hundred twenty-eight million, one hundred twenty-nine thousand, four hundred seventy-one".
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