Base | Representation |
---|---|
bin | 11101110001000010001… |
… | …001001011001001100001 |
3 | 21020112211101201102102221 |
4 | 131301002021023021201 |
5 | 232003203104242423 |
6 | 4203410214511041 |
7 | 300532514155432 |
oct | 35610211131141 |
9 | 7215741642387 |
10 | 2045514134113 |
11 | 71955244745a |
12 | 290526665481 |
13 | 11ab77b38a88 |
14 | 71009513489 |
15 | 3831db26e5d |
hex | 1dc4224b261 |
2045514134113 has 2 divisors, whose sum is σ = 2045514134114. Its totient is φ = 2045514134112.
The previous prime is 2045514134039. The next prime is 2045514134159. The reversal of 2045514134113 is 3114314155402.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1717651390464 + 327862743649 = 1310592^2 + 572593^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2045514134113 is a prime.
It is not a weakly prime, because it can be changed into another prime (2045514134413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1022757067056 + 1022757067057.
It is an arithmetic number, because the mean of its divisors is an integer number (1022757067057).
Almost surely, 22045514134113 is an apocalyptic number.
It is an amenable number.
2045514134113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2045514134113 is an equidigital number, since it uses as much as digits as its factorization.
2045514134113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28800, while the sum is 34.
Adding to 2045514134113 its reverse (3114314155402), we get a palindrome (5159828289515).
The spelling of 2045514134113 in words is "two trillion, forty-five billion, five hundred fourteen million, one hundred thirty-four thousand, one hundred thirteen".
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