Base | Representation |
---|---|
bin | 11101110101011111111… |
… | …111111111010011000101 |
3 | 21021000012122000011102202 |
4 | 131311133333333103011 |
5 | 232043013330310203 |
6 | 4205522135044245 |
7 | 301062410351144 |
oct | 35653777772305 |
9 | 7230178004382 |
10 | 2050310010053 |
11 | 720593604a98 |
12 | 291444810685 |
13 | 11b4605c81a6 |
14 | 7134243b75b |
15 | 384eebac388 |
hex | 1dd5ffff4c5 |
2050310010053 has 4 divisors (see below), whose sum is σ = 2065060441920. Its totient is φ = 2035559578188.
The previous prime is 2050310010031. The next prime is 2050310010079. The reversal of 2050310010053 is 3500100130502.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2050310010053 - 216 = 2050309944517 is a prime.
It is a super-2 number, since 2×20503100100532 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2050310010953) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7375215725 + ... + 7375216002.
It is an arithmetic number, because the mean of its divisors is an integer number (516265110480).
Almost surely, 22050310010053 is an apocalyptic number.
It is an amenable number.
2050310010053 is a deficient number, since it is larger than the sum of its proper divisors (14750431867).
2050310010053 is a wasteful number, since it uses less digits than its factorization.
2050310010053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14750431866.
The product of its (nonzero) digits is 450, while the sum is 20.
Adding to 2050310010053 its reverse (3500100130502), we get a palindrome (5550410140555).
The spelling of 2050310010053 in words is "two trillion, fifty billion, three hundred ten million, ten thousand, fifty-three".
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