Base | Representation |
---|---|
bin | 10011000110001000… |
… | …110110000010010001 |
3 | 1221220222001000010021 |
4 | 103012020312002101 |
5 | 313443020421213 |
6 | 13230333303441 |
7 | 1324052526331 |
oct | 230610660221 |
9 | 57828030107 |
10 | 20504076433 |
11 | 8772020115 |
12 | 3b82934b81 |
13 | 1c19c59309 |
14 | dc721d0c1 |
15 | 80013bd8d |
hex | 4c6236091 |
20504076433 has 2 divisors, whose sum is σ = 20504076434. Its totient is φ = 20504076432.
The previous prime is 20504076401. The next prime is 20504076469. The reversal of 20504076433 is 33467040502.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 20442422529 + 61653904 = 142977^2 + 7852^2 .
It is a cyclic number.
It is not a de Polignac number, because 20504076433 - 25 = 20504076401 is a prime.
It is not a weakly prime, because it can be changed into another prime (20504074433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10252038216 + 10252038217.
It is an arithmetic number, because the mean of its divisors is an integer number (10252038217).
Almost surely, 220504076433 is an apocalyptic number.
It is an amenable number.
20504076433 is a deficient number, since it is larger than the sum of its proper divisors (1).
20504076433 is an equidigital number, since it uses as much as digits as its factorization.
20504076433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60480, while the sum is 34.
The spelling of 20504076433 in words is "twenty billion, five hundred four million, seventy-six thousand, four hundred thirty-three".
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