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2050413543121 = 9973167649379
BaseRepresentation
bin11101110101100110001…
…010111011111011010001
321021000110211211012002211
4131311212022323323101
5232043221331334441
64205540314112121
7301065105356626
oct35654612737321
97230424735084
102050413543121
11720636a99a09
1229147341b641
1311b478ba7b68
14713520ac34d
1538508d0da81
hex1dd662bbed1

2050413543121 has 8 divisors (see below), whose sum is σ = 2053121368320. Its totient is φ = 2047707025008.

The previous prime is 2050413543083. The next prime is 2050413543197. The reversal of 2050413543121 is 1213453140502.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2050413543121 - 213 = 2050413534929 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2050413543421) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2832810 + ... + 3482188.

It is an arithmetic number, because the mean of its divisors is an integer number (256640171040).

Almost surely, 22050413543121 is an apocalyptic number.

It is an amenable number.

2050413543121 is a deficient number, since it is larger than the sum of its proper divisors (2707825199).

2050413543121 is an equidigital number, since it uses as much as digits as its factorization.

2050413543121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 653543.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 2050413543121 its reverse (1213453140502), we get a palindrome (3263866683623).

The spelling of 2050413543121 in words is "two trillion, fifty billion, four hundred thirteen million, five hundred forty-three thousand, one hundred twenty-one".

Divisors: 1 997 3167 649379 3157499 647430863 2056583293 2050413543121