Base | Representation |
---|---|
bin | 11101110101100110001… |
… | …010111011111100011101 |
3 | 21021000110211211012012122 |
4 | 131311212022323330131 |
5 | 232043221331340242 |
6 | 4205540314112325 |
7 | 301065105360065 |
oct | 35654612737435 |
9 | 7230424735178 |
10 | 2050413543197 |
11 | 720636a99a78 |
12 | 29147341b6a5 |
13 | 11b478ba7bc6 |
14 | 713520ac3a5 |
15 | 38508d0dad2 |
hex | 1dd662bbf1d |
2050413543197 has 2 divisors, whose sum is σ = 2050413543198. Its totient is φ = 2050413543196.
The previous prime is 2050413543083. The next prime is 2050413543257. The reversal of 2050413543197 is 7913453140502.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1676659829881 + 373753713316 = 1294859^2 + 611354^2 .
It is a cyclic number.
It is not a de Polignac number, because 2050413543197 - 210 = 2050413542173 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2050413542197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1025206771598 + 1025206771599.
It is an arithmetic number, because the mean of its divisors is an integer number (1025206771599).
Almost surely, 22050413543197 is an apocalyptic number.
It is an amenable number.
2050413543197 is a deficient number, since it is larger than the sum of its proper divisors (1).
2050413543197 is an equidigital number, since it uses as much as digits as its factorization.
2050413543197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 453600, while the sum is 44.
Adding to 2050413543197 its reverse (7913453140502), we get a palindrome (9963866683699).
The spelling of 2050413543197 in words is "two trillion, fifty billion, four hundred thirteen million, five hundred forty-three thousand, one hundred ninety-seven".
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