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205046193131 = 1315772784087
BaseRepresentation
bin1011111011110110110…
…1001001101111101011
3201121021000120212010022
42332331231021233223
511324413311140011
6234110311311055
720546143612223
oct2767555115753
9647230525108
10205046193131
1179a6125984a
12338a567b48b
1316449902480
149cd2369083
1555014a28db
hex2fbdb49beb

205046193131 has 4 divisors (see below), whose sum is σ = 220818977232. Its totient is φ = 189273409032.

The previous prime is 205046193089. The next prime is 205046193197. The reversal of 205046193131 is 131391640502.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 205046193131 - 218 = 205045930987 is a prime.

It is a super-2 number, since 2×2050461931312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 205046193091 and 205046193100.

It is not an unprimeable number, because it can be changed into a prime (205046198131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7886392031 + ... + 7886392056.

It is an arithmetic number, because the mean of its divisors is an integer number (55204744308).

Almost surely, 2205046193131 is an apocalyptic number.

205046193131 is a deficient number, since it is larger than the sum of its proper divisors (15772784101).

205046193131 is a wasteful number, since it uses less digits than its factorization.

205046193131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15772784100.

The product of its (nonzero) digits is 19440, while the sum is 35.

The spelling of 205046193131 in words is "two hundred five billion, forty-six million, one hundred ninety-three thousand, one hundred thirty-one".

Divisors: 1 13 15772784087 205046193131