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205104113 is a prime number
BaseRepresentation
bin11000011100110…
…10001111110001
3112021221100221122
430032122033301
5410001312423
632204032025
75040233114
oct1416321761
9467840848
10205104113
11a5859835
1258832615
13336535a6
141d35057b
15130168c8
hexc39a3f1

205104113 has 2 divisors, whose sum is σ = 205104114. Its totient is φ = 205104112.

The previous prime is 205104103. The next prime is 205104157. The reversal of 205104113 is 311401502.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 191213584 + 13890529 = 13828^2 + 3727^2 .

It is a cyclic number.

It is not a de Polignac number, because 205104113 - 218 = 204841969 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 205104091 and 205104100.

It is not a weakly prime, because it can be changed into another prime (205104103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 102552056 + 102552057.

It is an arithmetic number, because the mean of its divisors is an integer number (102552057).

Almost surely, 2205104113 is an apocalyptic number.

It is an amenable number.

205104113 is a deficient number, since it is larger than the sum of its proper divisors (1).

205104113 is an equidigital number, since it uses as much as digits as its factorization.

205104113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 205104113 is about 14321.4563854379. The cubic root of 205104113 is about 589.7366563909.

Adding to 205104113 its reverse (311401502), we get a palindrome (516505615).

The spelling of 205104113 in words is "two hundred five million, one hundred four thousand, one hundred thirteen".