Search a number
-
+
20514113 = 167122839
BaseRepresentation
bin100111001000…
…0010101000001
31102121020001222
41032100111001
520222422423
62011404425
7336236624
oct116202501
942536058
1020514113
1110641614
126a53715
134333439
142a1ddbb
151c033c8
hex1390541

20514113 has 4 divisors (see below), whose sum is σ = 20637120. Its totient is φ = 20391108.

The previous prime is 20514103. The next prime is 20514149. The reversal of 20514113 is 31141502.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20514113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20514091 and 20514100.

It is not an unprimeable number, because it can be changed into a prime (20514103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61253 + ... + 61586.

It is an arithmetic number, because the mean of its divisors is an integer number (5159280).

Almost surely, 220514113 is an apocalyptic number.

It is an amenable number.

20514113 is a deficient number, since it is larger than the sum of its proper divisors (123007).

20514113 is a wasteful number, since it uses less digits than its factorization.

20514113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 123006.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 20514113 is about 4529.2508210520. The cubic root of 20514113 is about 273.7479745199.

Adding to 20514113 its reverse (31141502), we get a palindrome (51655615).

The spelling of 20514113 in words is "twenty million, five hundred fourteen thousand, one hundred thirteen".

Divisors: 1 167 122839 20514113