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205244431113 = 368414810371
BaseRepresentation
bin1011111100100110000…
…1010111101100001001
3201121202211121101111210
42333021201113230021
511330320033243423
6234142112243333
720554101610431
oct2771141275411
9647684541453
10205244431113
117a053148997
123393bb40549
131647b9c0757
149d1080d2c1
155513aaeb93
hex2fc9857b09

205244431113 has 4 divisors (see below), whose sum is σ = 273659241488. Its totient is φ = 136829620740.

The previous prime is 205244431103. The next prime is 205244431121. The reversal of 205244431113 is 311134442502.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 205244431113 - 25 = 205244431081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (205244431103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34207405183 + ... + 34207405188.

It is an arithmetic number, because the mean of its divisors is an integer number (68414810372).

Almost surely, 2205244431113 is an apocalyptic number.

It is an amenable number.

205244431113 is a deficient number, since it is larger than the sum of its proper divisors (68414810375).

205244431113 is an equidigital number, since it uses as much as digits as its factorization.

205244431113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 68414810374.

The product of its (nonzero) digits is 11520, while the sum is 30.

Adding to 205244431113 its reverse (311134442502), we get a palindrome (516378873615).

The spelling of 205244431113 in words is "two hundred five billion, two hundred forty-four million, four hundred thirty-one thousand, one hundred thirteen".

Divisors: 1 3 68414810371 205244431113