Base | Representation |
---|---|
bin | 111101001100001… |
… | …1001011110010011 |
3 | 12022002111012001111 |
4 | 1322120121132103 |
5 | 13201110404042 |
6 | 535423314151 |
7 | 101611022623 |
oct | 17230313623 |
9 | 5262435044 |
10 | 2053216147 |
11 | 963a94754 |
12 | 49374b957 |
13 | 2694ba5c8 |
14 | 15698c883 |
15 | c03c5517 |
hex | 7a619793 |
2053216147 has 2 divisors, whose sum is σ = 2053216148. Its totient is φ = 2053216146.
The previous prime is 2053216117. The next prime is 2053216189. The reversal of 2053216147 is 7416123502.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2053216147 is a prime.
It is a super-4 number, since 4×20532161474 (a number of 38 digits) contains 4444 as substring. Note that it is a super-d number also for d = 3.
It is not a weakly prime, because it can be changed into another prime (2053216117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1026608073 + 1026608074.
It is an arithmetic number, because the mean of its divisors is an integer number (1026608074).
Almost surely, 22053216147 is an apocalyptic number.
2053216147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2053216147 is an equidigital number, since it uses as much as digits as its factorization.
2053216147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10080, while the sum is 31.
The square root of 2053216147 is about 45312.4281737362. The cubic root of 2053216147 is about 1270.9980678105.
Adding to 2053216147 its reverse (7416123502), we get a palindrome (9469339649).
The spelling of 2053216147 in words is "two billion, fifty-three million, two hundred sixteen thousand, one hundred forty-seven".
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