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205433250041 is a prime number
BaseRepresentation
bin1011111101010011000…
…1101010000011111001
3201122020222220101101102
42333110301222003321
511331211403000131
6234212535301145
720561553546065
oct2772461520371
9648228811342
10205433250041
117a13a794398
123399321a7b5
13164abb61726
149d2b920aa5
15552545b1cb
hex2fd4c6a0f9

205433250041 has 2 divisors, whose sum is σ = 205433250042. Its totient is φ = 205433250040.

The previous prime is 205433250007. The next prime is 205433250083. The reversal of 205433250041 is 140052334502.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 156147474025 + 49285776016 = 395155^2 + 222004^2 .

It is a cyclic number.

It is not a de Polignac number, because 205433250041 - 222 = 205429055737 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 205433249986 and 205433250013.

It is not a weakly prime, because it can be changed into another prime (205433450041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 102716625020 + 102716625021.

It is an arithmetic number, because the mean of its divisors is an integer number (102716625021).

Almost surely, 2205433250041 is an apocalyptic number.

It is an amenable number.

205433250041 is a deficient number, since it is larger than the sum of its proper divisors (1).

205433250041 is an equidigital number, since it uses as much as digits as its factorization.

205433250041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 29.

Adding to 205433250041 its reverse (140052334502), we get a palindrome (345485584543).

The spelling of 205433250041 in words is "two hundred five billion, four hundred thirty-three million, two hundred fifty thousand, forty-one".