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20611414353 = 36870471451
BaseRepresentation
bin10011001100100010…
…010011100101010001
31222012110000100001210
4103030202103211101
5314203010224403
613245130050333
71326525063015
oct231442234521
958173010053
1020611414353
118817673742
123bb28799a9
131c3626ba8a
14dd75a0545
15809790b03
hex4cc893951

20611414353 has 4 divisors (see below), whose sum is σ = 27481885808. Its totient is φ = 13740942900.

The previous prime is 20611414333. The next prime is 20611414367. The reversal of 20611414353 is 35341411602.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 20611414353 - 25 = 20611414321 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 20611414353.

It is not an unprimeable number, because it can be changed into a prime (20611414303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3435235723 + ... + 3435235728.

It is an arithmetic number, because the mean of its divisors is an integer number (6870471452).

Almost surely, 220611414353 is an apocalyptic number.

It is an amenable number.

20611414353 is a deficient number, since it is larger than the sum of its proper divisors (6870471455).

20611414353 is an equidigital number, since it uses as much as digits as its factorization.

20611414353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6870471454.

The product of its (nonzero) digits is 8640, while the sum is 30.

Adding to 20611414353 its reverse (35341411602), we get a palindrome (55952825955).

The spelling of 20611414353 in words is "twenty billion, six hundred eleven million, four hundred fourteen thousand, three hundred fifty-three".

Divisors: 1 3 6870471451 20611414353