Base | Representation |
---|---|
bin | 101111110000000011001010… |
… | …101110100100010010111111 |
3 | 1000112120202211111101210011001 |
4 | 233300003022232210102333 |
5 | 210011301212230011033 |
6 | 2022353152422311131 |
7 | 62143505413334245 |
oct | 5760031256442277 |
9 | 1015522744353131 |
10 | 210010122110143 |
11 | 60a08879a84553 |
12 | 1b679450b884a7 |
13 | 9024b3c4ba094 |
14 | 39c07891c0795 |
15 | 1942ca2960e7d |
hex | bf00caba44bf |
210010122110143 has 2 divisors, whose sum is σ = 210010122110144. Its totient is φ = 210010122110142.
The previous prime is 210010122110099. The next prime is 210010122110231. The reversal of 210010122110143 is 341011221010012.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 210010122110143 - 245 = 174825750021311 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 210010122110143.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (210010122116143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105005061055071 + 105005061055072.
It is an arithmetic number, because the mean of its divisors is an integer number (105005061055072).
Almost surely, 2210010122110143 is an apocalyptic number.
210010122110143 is a deficient number, since it is larger than the sum of its proper divisors (1).
210010122110143 is an equidigital number, since it uses as much as digits as its factorization.
210010122110143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 210010122110143 its reverse (341011221010012), we get a palindrome (551021343120155).
The spelling of 210010122110143 in words is "two hundred ten trillion, ten billion, one hundred twenty-two million, one hundred ten thousand, one hundred forty-three".
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