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210011011022143 is a prime number
BaseRepresentation
bin101111110000000011111111…
…101101011111110100111111
31000112120212010110001012011201
4233300003333231133310333
5210011310022310202033
62022353420535000331
762143536426062362
oct5760037755376477
91015525113035151
10210011011022143
1160a09195823271
121b67965a8090a7
139024c51700906
1439c08312920d9
151942d059ec47d
hexbf00ffb5fd3f

210011011022143 has 2 divisors, whose sum is σ = 210011011022144. Its totient is φ = 210011011022142.

The previous prime is 210011011022051. The next prime is 210011011022167. The reversal of 210011011022143 is 341220110110012.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 210011011022143 - 233 = 210002421087551 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 210011011022143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (210011011022173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105005505511071 + 105005505511072.

It is an arithmetic number, because the mean of its divisors is an integer number (105005505511072).

Almost surely, 2210011011022143 is an apocalyptic number.

210011011022143 is a deficient number, since it is larger than the sum of its proper divisors (1).

210011011022143 is an equidigital number, since it uses as much as digits as its factorization.

210011011022143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 210011011022143 its reverse (341220110110012), we get a palindrome (551231121132155).

The spelling of 210011011022143 in words is "two hundred ten trillion, eleven billion, eleven million, twenty-two thousand, one hundred forty-three".