Base | Representation |
---|---|
bin | 101111110000000100000110… |
… | …110111111100011101000111 |
3 | 1000112120212102211011221001111 |
4 | 233300010012313330131013 |
5 | 210011310244041420401 |
6 | 2022353440510505451 |
7 | 62143542415431154 |
oct | 5760040667743507 |
9 | 1015525384157044 |
10 | 210011131201351 |
11 | 60a09247647727 |
12 | 1b679692b05287 |
13 | 9024c7058b27c |
14 | 39c084321722b |
15 | 1942d1133ae51 |
hex | bf0106dfc747 |
210011131201351 has 2 divisors, whose sum is σ = 210011131201352. Its totient is φ = 210011131201350.
The previous prime is 210011131201303. The next prime is 210011131201367. The reversal of 210011131201351 is 153102131110012.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 210011131201351 - 245 = 174826759112519 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (210011131202351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105005565600675 + 105005565600676.
It is an arithmetic number, because the mean of its divisors is an integer number (105005565600676).
Almost surely, 2210011131201351 is an apocalyptic number.
210011131201351 is a deficient number, since it is larger than the sum of its proper divisors (1).
210011131201351 is an equidigital number, since it uses as much as digits as its factorization.
210011131201351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 180, while the sum is 22.
Adding to 210011131201351 its reverse (153102131110012), we get a palindrome (363113262311363).
The spelling of 210011131201351 in words is "two hundred ten trillion, eleven billion, one hundred thirty-one million, two hundred one thousand, three hundred fifty-one".
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