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21001303100103 = 38423831109387
BaseRepresentation
bin1001100011001101111110…
…01101100000101011000111
32202100201000220220021102120
410301212333031200223013
510223041132043200403
6112355510534341023
74265202603652404
oct461467715405307
982321026807376
1021001303100103
11676766a108367
122432239aba773
13b94550531611
1452867b7912ab
1526645ac00e53
hex1319bf360ac7

21001303100103 has 8 divisors (see below), whose sum is σ = 28005061938048. Its totient is φ = 13999206497784.

The previous prime is 21001303100021. The next prime is 21001303100179. The reversal of 21001303100103 is 30100130310012.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 21001303100103 - 228 = 21001034664647 is a prime.

It is a super-2 number, since 2×210013031001032 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21001303100003) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 415529425 + ... + 415579962.

It is an arithmetic number, because the mean of its divisors is an integer number (3500632742256).

Almost surely, 221001303100103 is an apocalyptic number.

21001303100103 is a deficient number, since it is larger than the sum of its proper divisors (7003758837945).

21001303100103 is an equidigital number, since it uses as much as digits as its factorization.

21001303100103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 831117813.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 21001303100103 its reverse (30100130310012), we get a palindrome (51101433410115).

The spelling of 21001303100103 in words is "twenty-one trillion, one billion, three hundred three million, one hundred thousand, one hundred three".

Divisors: 1 3 8423 25269 831109387 2493328161 7000434366701 21001303100103