Base | Representation |
---|---|
bin | 1100001110010111000… |
… | …1001100110001011111 |
3 | 202002002012002112120111 |
4 | 3003211301030301133 |
5 | 11420101401410142 |
6 | 240251230030451 |
7 | 21113216452522 |
oct | 3034561146137 |
9 | 662065075514 |
10 | 210013310047 |
11 | 81080047252 |
12 | 34851048427 |
13 | 16a5b9b99c8 |
14 | a243d0abb9 |
15 | 56e25b0e17 |
hex | 30e5c4cc5f |
210013310047 has 2 divisors, whose sum is σ = 210013310048. Its totient is φ = 210013310046.
The previous prime is 210013309997. The next prime is 210013310051. The reversal of 210013310047 is 740013310012.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 210013310047 - 223 = 210004921439 is a prime.
It is a super-4 number, since 4×2100133100474 (a number of 46 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (210013314047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105006655023 + 105006655024.
It is an arithmetic number, because the mean of its divisors is an integer number (105006655024).
Almost surely, 2210013310047 is an apocalyptic number.
210013310047 is a deficient number, since it is larger than the sum of its proper divisors (1).
210013310047 is an equidigital number, since it uses as much as digits as its factorization.
210013310047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 22.
Adding to 210013310047 its reverse (740013310012), we get a palindrome (950026620059).
The spelling of 210013310047 in words is "two hundred ten billion, thirteen million, three hundred ten thousand, forty-seven".
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