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2100140412013 = 72910345519271
BaseRepresentation
bin11110100011111010000…
…111111000110001101101
321102202211101200212021201
4132203322013320301231
5233402041421141023
64244442521325501
7304505302651030
oct36437207706155
97382741625251
102100140412013
1173a73456a576
1229b030936891
13123072196837
147390c421017
1539969700bad
hex1e8fa1f8c6d

2100140412013 has 8 divisors (see below), whose sum is σ = 2482924625280. Its totient is φ = 1738047237360.

The previous prime is 2100140411989. The next prime is 2100140412059. The reversal of 2100140412013 is 3102140410012.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-2100140412013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2100140472013) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5172759433 + ... + 5172759838.

It is an arithmetic number, because the mean of its divisors is an integer number (310365578160).

Almost surely, 22100140412013 is an apocalyptic number.

It is an amenable number.

2100140412013 is a deficient number, since it is larger than the sum of its proper divisors (382784213267).

2100140412013 is a wasteful number, since it uses less digits than its factorization.

2100140412013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10345519307.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 2100140412013 its reverse (3102140410012), we get a palindrome (5202280822025).

The spelling of 2100140412013 in words is "two trillion, one hundred billion, one hundred forty million, four hundred twelve thousand, thirteen".

Divisors: 1 7 29 203 10345519271 72418634897 300020058859 2100140412013