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210014432013 = 370004810671
BaseRepresentation
bin1100001110010111010…
…1011110101100001101
3202002002021012112121210
43003211311132230031
511420102143311023
6240251310045033
721113232134541
oct3034565365415
9662067175553
10210014432013
11810807431a1
12348514a9779
1316a5bcc05a9
14a24411da21
1556e2733593
hex30e5d5eb0d

210014432013 has 4 divisors (see below), whose sum is σ = 280019242688. Its totient is φ = 140009621340.

The previous prime is 210014431997. The next prime is 210014432027. The reversal of 210014432013 is 310234410012.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 210014432013 - 24 = 210014431997 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (210014432213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35002405333 + ... + 35002405338.

It is an arithmetic number, because the mean of its divisors is an integer number (70004810672).

Almost surely, 2210014432013 is an apocalyptic number.

It is an amenable number.

210014432013 is a deficient number, since it is larger than the sum of its proper divisors (70004810675).

210014432013 is an equidigital number, since it uses as much as digits as its factorization.

210014432013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70004810674.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 210014432013 its reverse (310234410012), we get a palindrome (520248842025).

The spelling of 210014432013 in words is "two hundred ten billion, fourteen million, four hundred thirty-two thousand, thirteen".

Divisors: 1 3 70004810671 210014432013